find probability of getting red ball randomly from a bag in which 3 red,5 blue and 6 yellow ball contains
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23
45
38
47
Answer :
D
Solution :
According to question ,
probability that no ball is green
10C1×9C115×14=9015×14=37
required probability =1−37=47
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Total number of outcomes = 3 + 5 + 6 = 14
Favourable outcomes = 3
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