Question

Find probability that four digit number compromising number comprising the digits 2, 5, 6 and 7 would be divisible by 4​

Answer 1

Answer:

0

Step-by-step explanation:

there is no no. divisible by 4

Answer 2

Step by step solution :

• Since there are four digits, all distinct, the total number of four digit numbers that can be formed without any restriction is 4 or 4 x 3 x 2 x 1 or 24.
• Now a four digit number would be divisible by 4 if the number formed by the last two digits is divisible by 4.
• This could happen when the four digit number ends with 52 or 56 or 72 or 76. If we fix the last two digits by 52, and then the 1st two places of the four digit number can be filled up using the remaining 2 digits in 2! or 2 ways.
• Thus there are 2 four digit numbers that end with 52. Proceeding in this maruner, we find that the number of four digit numbers that are divisible by 4 is 4 x 2 or 5.
• If (A) denotes the event that any four digit number using the given digits would be divisible by 4, then we have

P(A) = 8/24 = 1/3