find product (1+root 3)(6-root 3
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( 1 + √3 ) × ( 6 - √3 )
= 6 + 6√3 - √3 - √3²
= 6 + 5√3 - 3
= 3 + 5√3
( 1 + √3 ) × ( 6 - √3 )
= 6 + 6√3 - √3 - √3²
= 6 + 5√3 - 3
= 3 + 5√3
Answered by
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(1+√3)(6-√3)
(6-√3+6√3-3)
(3+5√3)
(6-√3+6√3-3)
(3+5√3)
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