Question

find product (2x+4) (3x^2-6x+7)​

Answer 1

Answer:

$6 {x}^{3} - 10x + 28$

Step-by-step explanation:

$(2x+4) (3x^2-6x+7) \\ = 2x (3x^2-6x+7) + 4(3x^2-6x+7) \\ = 6 {x}^{3} - 12 {x}^{2} + 14x + 12 {x}^{2} - 24x + 28 \\ = 6 {x}^{3} +(- 12 {x}^{2} + 12 {x}^{2} )+(14x - 24x )+ 28 \\= 6 {x}^{3} - 10x + 28$