Math, asked by ramankaur11293, 4 days ago

Find product of (2a + 3b + 4c), (3a ^ 2 * b * c) .​

Answers

Answered by 21sv0056abhiram
1

Answer:

12a+6b+8c

Step-by-step explanation:

(2a + 3b + 4c), (3a ^ 2 * b * c)

=2a + 3b + 4c x 3a ^ 2 * b * c

=2a + 3b + 4c x 3a*a * b * c

=6a+3b+4c*1a*b*c

=12a+6b+8c

Therefore the answer is 12a+6b+8c

Answered by shravanipatil5328
0

Answer:

12a+6b+8c

Step-by-step explanation:  

To find the product :

 

(2a + 3b + 4c), (3a ^ 2 * b * c)

=2a + 3b + 4c x 3a ^ 2 * b * c

=2a + 3b + 4c x 3a*a * b * c

=6a+3b+4c*1a*b*c

=12a+6b+8c

Thus,

the answer is 12a+6b+8c

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