Question

Find product of (2x^2 + 3y + 3)(2y – 3x^2) and find the value of that product when x = - 2 and y = 5​

Answer 1

Answer:

Hope this will help you ❤️...

Answer 2

Answer:

Step-by-step explanation:

$\bf (2x^2 + 3y + 3)(2y-3x^2)\\\\Putting\ x=-2 \ and \ y=5\\\\=[ 2(-2)^2+3(5)+3] [ 2(5)-3(-2)^2]\\\\=[ 2\times4+15+3][10-3\times4]\\\\=26\times-2=-52$