find product of 3×-2y-3;x-2y2-
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Answer:
Step-by-step explanation:
Given,
3x - 2y - 3 ; x - 2y ^2
= (3x -2y - 3) (x - 2y ^2)
= (3x × x ) - (3x × 2y^2) - (2y × x ) - [ 2y × (-2y ^2)] - (3 × x ) - [3 × (-2y ^2)]
= 3x ^2 - 6xy^2 - 2xy + 4y ^3 - 3x + 6y^2
= 4y^3 + 3x ^2 + 6y^2 - 6xy^2 - 3x -2xy
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