find product of the zeros of the polynomial m square - 17 m + 72
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Answered by
3
Let p(m) be the representation of the given polynomial
We have,
p(m)=m²-17m+72
Let @ and ß be the zeros
For product of zeros,it would be: constant term/x²coeffiecient
Here,
@ß=72
Answered by
5
Answer:
72
Step-by-step explanation:
m^2-17m+72
m^2-8m-9m+72
m(m-8)-9(m-8)
(m-8)(m-9)
m=8;m=9
Here,8 and 9 are the zeros of polynomial
product of 8 and 9 is 72.
Hope it helps you
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