Find product of two consecutive positive numbers such that the sum of their squares is equal to 113.
Answers
Answered by
0
Answer:
x)
2
+(x+2)
2
=130
⇒x
2
+x
2
+4+4x=130(∵(a+b)
2
=a
2
+b
2
+2ab)
⇒2x
2
+4x+4−130=0
⇒2x
2
+4x−126=0
⇒2(x
2
+2x−63)=0
⇒x
2
+2x−63=0
⇒x
2
+9x−7x−63=0
⇒x(x+9)−7(x+9)=0
⇒(x−7)=0,(x+9)=0
⇒x=7,x=−9
Since it is given that x is a positive odd number, thus x=7.
Now, x+2=7+2=9
Hence, the two consecutive positive odd numbers are 7 and 9.
there is difference of 130
but It will helps you
Answered by
0
Answer:
let the number be x^2 and (x+1)^2
Step-by-step explanation:
2x^2+1=113
2x^2=113-1
2x^2=112
x^2=112÷2
x^2=56
(x+1)^2=2809
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