Question

find products (3x+4y) (x²-xy+y²)​

Answer 1

Step-by-step explanation:

3x³ - 3x²y + 3xy² + 4x²y - 4xy² + 4y³

3x³ + 4y³ + x²y - xy²

Answer 2

To find  : product of $(3x + 4y ) (x^{2} -xy + y^{2} )$

Solution :

• To find product of $(3x + 4y ) (x^{2} -xy + y^{2} )$  we multiply given terms of first bracket by the terms of second bracket one by one .
• Multiplication is a process of repetitive addition of integers.
• Multiplication rules for integers :

1. If two negative integers are multiplied then the product obtained is positive integer. i.e. $(-) \times(-)=+$
2. If one negative and one positive integers are multiplied then the product obtained is negative integer. i.e. $(-) \times(+)=-$
3. If both positive integers are multiplied then the product obtained is positive integer. i.e. $(+) \times(+)=+$

• Therefore multiplying both brackets we get ,
• $(3x + 4y ) (x^{2} -xy + y^{2} )$  

       $= 3x^{3} -3x^{2} y + 3xy^{2} + 4x^{2} y-4xy^{2}+ 4y^{3}$  

       $= 3x^{3} +x^{2} y-xy^{2} +4y^{3}$

Hence , product is $3x^{3} +x^{2} y-xy^{2} +4y^{3}$ .