find ∠prq, if ∠opq = 50º
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let ΔPOQ be an isosceles triangle then ANG.PQO=ANG.OPQ=50°
ANG.POQ+ANG.PQO+ANG.OPQ=180°
ANG.POQ+50°+50°=180°
ANG.POQ=180°-100°
ANG.POQ=80°
So, ang.PRQ=80°/2=40°
Therefore,ANG.PRQ=40°
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