Math, asked by jyanamahajan01, 1 year ago

Find px whose zeroes are -3,4
Can we do like this
X= -3,x=4
(X+3)(x-4)
X^2+3x-4x-12
X^2-x-12

Answers

Answered by babushall
1

Find px whose zeroes are -3,4

Can we do like this

X= -3,x=4

(X+3)(x-4)

X^2+3x-4x-12

X^2-x-12

yep you can do like this or use the quadratic equation formula.

quadratic equations formula is =》

x^2-x(alpha +beta)+(alpha×beta)=0

x^2-x(-3+4)+(-3×[+4])=0.

=》x^2-x(1)+(-12)=0.

=》X^2-x-12=0.

both answers are same.....comment if you are not clear.....


jyanamahajan01: Today was my exam n i have done the way showed above
jyanamahajan01: This means my method is correct
babushall: both methods are correct
babushall: until and unless the examiner does not specify any method
Similar questions