Find px whose zeroes are -3,4
Can we do like this
X= -3,x=4
(X+3)(x-4)
X^2+3x-4x-12
X^2-x-12
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Find px whose zeroes are -3,4
Can we do like this
X= -3,x=4
(X+3)(x-4)
X^2+3x-4x-12
X^2-x-12
yep you can do like this or use the quadratic equation formula.
quadratic equations formula is =》
x^2-x(alpha +beta)+(alpha×beta)=0
x^2-x(-3+4)+(-3×[+4])=0.
=》x^2-x(1)+(-12)=0.
=》X^2-x-12=0.
both answers are same.....comment if you are not clear.....
jyanamahajan01:
Today was my exam n i have done the way showed above
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