Find Pythagorean Triplet of [ 11 , 60 ,61 ]
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Answer:
Solution. The square of the largest number is equal to the sum of the squares of the other two numbers. ∴ (11, 60, 61) is a pythagorean triplet.
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Longest Side² :
➟ 61²
➟3721 ──── 1
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Sum of Square of Two Other Sides² :
➟ 11² + 60²
➟ 121 + 3600
➟ 3721 ──── 2
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From 1st Nd 2nd
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Longest Side² = Sum of Square of Two Other Sides².
⠀⠀
Therefore..,
[ 11 , 60 ,61 ] are Pythagorean Triplet.
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