Find Pythagorean triplet one of whose number is
(i) 257
) 65
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Answer:
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3
Answer:
2=65
(2m) (m²+1) (m²-1)
2m=65
m=65/2=32.5
m=32.5
m²+1= (32.5²+1)
1056.25+1
m²+1=1056.26
(m²-1)=32.5²-1
1056.25-1=1056.24
(m²-1)= 1056.24
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