find Pythagorean triplet whose one member is 5
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Answered by
17
let the number given be a
then if a<3 then no triplets will form
if a is even, then b=(a/2)^2 -1 , c=b+2
if a is odd, then b=(a^2–1)/2, c=b+1
By this u can find the other two numbers so let your a be 5 and then u can find out by the above method.....
then if a<3 then no triplets will form
if a is even, then b=(a/2)^2 -1 , c=b+2
if a is odd, then b=(a^2–1)/2, c=b+1
By this u can find the other two numbers so let your a be 5 and then u can find out by the above method.....
Answered by
3
Answer: the required answer is 3,4,5
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