find Pythagorean triplet with the smallest number as 10
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For every natural no. 2m,m*2,m*2-1 is a pythagorean triplet.
Let m*2+1=10
m*2=9=m=3
Therefore, 2m=6, m*2-1=8
Thus, the triplet is 6,8,10. But 10 is not the smallest member of this.
So, let us try 2m=10
m=5
Therefore,
m*2+1=25+1
=26
m*2-1=25-1
=24
Thus, the required pythagorean triplet are 10,24,26
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10, 24, 26
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