Find pythoganos triplet in which one member is 12.
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If we take m^2-1=12
Then m^2=12+1=13
Then the value of m will not be an integer
So we try to take m^2+1=12 Again m^2=11
will not give an integer value for m
So let us take 2m = 12
then m=6
Thus m^2−1=36−1=35 and m^2+1=36+1=37
Therefore the required triplet is 12, 35, 37
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