Question

Find
pythogoras triplet whoose
largest
number is 145 with explanation and solving please​

Answer 1

Answer:

24, 143, 145

we know pythagorean tripets are

$2x \\ {x}^{2} - 1 \\ {x}^{2} + 1$

so

${x}^{2} + 1 = 145 \\ {x}^{2} = 144 \\ x = 12$

so required triplet is

$2x = 2 \times 12 = 24 \\ {x}^{2} - 1 = {12}^{2} - 1 = 144 - 1 = 143 \\ {x}^{2} + 1 = {12}^{2} + 1 = 144 + 1 = 145$