Question

find pythogorean triplet where one number is 12 ​

Answer 1

Answer:

step 1 : 2m = 12

step 2 : m= 12/2

m = 6

step 3 : m^2+1

step 4 : 6^2+1

36+1

=37

step 5 : m^2-1

step 6 : 6^2 -1

36 -1

=35

(6,37,35)=(2m,m^2+1,m^2-1)

Answer 2

Answer:

12²+5² = 13²

Step-by-step explanation:

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