Find q(0) if q(y)= (y-1)(y+1)*
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Answer:
x^1/p = y^1/q = z^1/r
=> y = x^q/p & z = x^r/p
=> x *y *z = x ^ (1 + q/p + r/p) = 1
=> x ^ [(p+q+r)/p] = 1
=> 1 can be written as x ^ 0
=> x ^0 = 1
=>hence x ^ [(p+q+r)/p] = x ^ 0 = 1
=> p+q+r = 0
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