Question

find quadratic equation. 6/x=1+x​

Answer 1

Answer:

6 = x + x²

x² + x - 6 =0

x²+3x-2x-6=0

x(x+3) -2(x+3)=0

(x+3)(x-2)=0

x=-3. OR x=2

HOPE IT HELPS :)

Answer 2

Step-by-step explanation:

$\bf\frac{6}{x}=1+x$

$\bf\frac{6}{x}=1+x,x≠0$

$\bf6=(1+x)×x$

$\bf6-(1+x)×x=0$

$\bf6-(x+x²)=0$

$\bf6-x-x²=0$

$\bf-x²-x+6=0$

$\bf x²+x-6=0$

$\bf x²+3x-2x-6=0$

$\bf x×(x+3)-2(x+3)=0$

$\bf (x+3)×(x-2)=0$

$\bf x+3=0 \\ \bf x - 3 = 0$

$\bf x = -3 \\ \bf x = 2 \\ \bf x ≠ 0$

$\bf x1 = -3 \\ \bf x2 = 2$