Question

Find quadratic equations where zeo are -8/3 , 4/3

Answer 1

Step-by-step explanation:

$equation = {x}^{2} - (a + b)x + ab$

a=-8/3, b=4/3

a+b=-8/3+4/3=-8+4/3=-4/3.

ab=-8/3(4/3)=-32/9.

Substituting the obtained values in equation, we get:

x²-(-4/3)+(-32/9)=0

x²+4/3-32/9=0

By taking LCM:

9x²+12x-32=0 is the quadractic equation.

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Answer 2

Answer:

answer attached in photo