Question

find quadratic polynomial 1/3,-1 as the sum and product oF it's zero resp.​

Answer 1

Answer:

k( 3x²-1x-3 )

Explanation:

We have,

Sum of the Zeros = 1/3

Product of the zeros = -1

So the quadratic equation is

= k( x² - (sum of zeros)x + product of zeros)

= k( x² - 1/3x -1)

= k( 3x²-1x-3)

where k is a constant.

Answer 2

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Given:-

• sum of zeroes of a polynomial is 1/3
• product of zeroes is (-1)

To find:-

• the polynomial

Solution:-

we know,

Skeletal quadratic polynomial:-

${x}^{2} - (sum \: of \: zereos)x + product \: of \: zeroes)$

Now,

By putting the given value,we get

${x }^{2} - \frac{1}{3} x + ( - 1)$

$= {x}^{2} - \frac{1}{3} x - 1$

$= 3 {x}^{2} - x - 3$

Hence,the required polynomial is

$3 {x}^{2} - x - 3$

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