Find quadratic polynomial as sum and product of its zeroes of -1/4 , 1/4
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Answer:
The answer will be;
4x^2 - x + 1 = 0;
Step-by-step explanation:
Given;
sum of zeroes = -1/4;
product of zeroes = 1/4;
Let a (coefficient of x^2) be 1. (i)
Thus, sum of zeroes = -b/a;
-1/4 = -b/1;
b = 1/4; (ii)
Product of zeroes = c/a;
1/4 = c/1;
c = 1/4; (iii)
General form of a quadritic equation is;
ax^2 - bx + c = 0;
From statement (i) and equation (ii) and (iii);
= (1)x^2 - (1/4)x + (1/4) = 0;
= x^2 - x/4 + 1/4 = 0;
= (4x^2 - x + 1) / 4 = 0;
= 4x^2 - x + 1 = 0.
That's all.
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