Question

Find quadratic polynomial having Sum =1/6, product = - 1/3 of its zeroes

Answer 1

Step-by-step explanation:

Solution:-

sum of ploynomial

$( \alpha + \beta ) = \frac{1}{6}$

product of ploynomial

$( \alpha \times \beta ) = \frac{ - 1}{3}$

general form of quadratic polynomial is

${x}^{2} - ( \alpha + \beta )x + ( \alpha \times \beta )$

putting constant term as K

$k( {x}^{2} - ( \alpha + \beta )x + ( \alpha \times \beta ))$

now put the value

$k( {x}^{2} - ( \frac{1}{6} )x + ( \frac{ - 1}{3} )) = 0$

Answer:-

$k( {x}^{2} - ( \frac{1}{6} )x + ( \frac{ - 1}{3} )) = 0$