find quadratic polynomial if zeroes are
1/√2 , -√3/2
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zeros = 1/√2 and -√3/2
sum of the zeros= 1/√2+ (-√3/2)
√2-√3/2
√2-√3/2 = -b/a
b=√3-√2
a=2
product= 1/√2 × -√3/2
-√3/2√2
c= -√3
a= 2√2
but above a was coming √2 so we will multiply b and a by √2
therefore b=√6-2
and a=2√2
general equation = ax^2+bx+c
2√2x^2+(√6-2)x-√3
sum of the zeros= 1/√2+ (-√3/2)
√2-√3/2
√2-√3/2 = -b/a
b=√3-√2
a=2
product= 1/√2 × -√3/2
-√3/2√2
c= -√3
a= 2√2
but above a was coming √2 so we will multiply b and a by √2
therefore b=√6-2
and a=2√2
general equation = ax^2+bx+c
2√2x^2+(√6-2)x-√3
sandeep328:
its not -3/√2 ....... its -√3/2
plz write correct answer
corrected
yeah...... thanx
wlcm
plz mark it as the brainliest if u like it
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here is your answer and I think it may help you
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thank you.......
can you do one other question
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