Question

find quadratic polynomial if zeroes are
1/√2 , -√3/2

Answer 1

zeros = 1/√2 and -√3/2
sum of the zeros= 1/√2+ (-√3/2)
√2-√3/2
√2-√3/2 = -b/a
b=√3-√2
a=2

product= 1/√2 × -√3/2
-√3/2√2
c= -√3
a= 2√2

but above a was coming √2 so we will multiply b and a by √2
therefore b=√6-2
and a=2√2

general equation = ax^2+bx+c
2√2x^2+(√6-2)x-√3

Answer 2

here is your answer and I think it may help you