Question

Find quadratic polynomial whose sum of zeros is 21/8 andproduct is 5/16

Answer 1

Here :

Given

sum of zeroes = 21/8

and

product of zeroes=5/16

polynomial= x^2-(sum of zeroes)x+(product of zeroes)=0

so , put the value we get ,

p(x)=x^2-21/8(x)+5/16=0

p(x) =16x^2-42x+5=0

this is the required answer

Answer 2

Answer:

16x² - 42x + 5 = 0

Step-by-step explanation:

Sum of roots, α + β = 21/8.

Product of roots, αβ = 5/16.

The quadratic equation will be of form x² - (α + β)x + αβ = 0

=> x² - (21/8)x + 5/16 = 0

=> 16x² - 42x + 5 = 0 (taking 16 LCM)