Question

Find quadratic polynomial whose sum of zeros is minus 13 and product of zeroes is 7

Answer 1

Answer:

x^2+13x+7=0

Step-by-step explanation:

alpha+beta=-13;alpha*beta=7

q.p=x^2-(alpha+beta)x+(alpha*beta)

     =x^2+13x+7

     

Answer 2

Answer: The polynomial is $x^{2} + 13x + 7$

Step-by-step explanation:

Sum of roots = -b/a = -(-13)/1 = +13/1

Product of roots = c/a = 7/1

Therefore a = 1,  b = -13, c = 7

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