Question

find quadratic polynomial whose zeroes are 3/2 and -1​

Answer 1

Answer:

The answer is x^2 -(1/2)x -(3/2)

Answer 2

Answer:

x²-$\frac{1}{2}$+$\frac{(-3)}{2}$

Step-by-step explanation:

Given⤵

➡Zeros are 3/2 and -1 .

To find⤵

➡Quadratic polynomial.

Solution⤵

➡Sum of zeros

= $\frac {3}{2} +(-1)$

= $\frac{3-2}{2}$

= $\frac{1}{2}$

➡Product of zeros

= $\frac{3}{2}×(-1)$

=$\frac{-3}{2}$

⚫Now, using formula

x²-(sum of zeros)x+product of zeros

➡x²-$\frac{1}{2}$+$\frac{(-3)}{2}$

✅Hence, the quadratic polynomial whose zeros are 3/2 and -1 is x²-$\frac{1}{2}$+$\frac{(-3)}{2}$.

✔Extra points⤵

✡ x²-(sum of zeros)x+product of zeros

Hope this is helpful to you!