Question

find quadratic polynomial whose zeroes are l/5,-4/7​

Answer 1

Answer:

x^2-1/5x-4/7

this the answer

Answer 2

Therefore the required quadratic polynomial whose zeroes are 1/5 and -4/7 is '35x² + 13x - 4 = 0'.

Given:

The zeroes of the quadratic polynomial = 1/5 and -4/7

To Find:

The quadratic polynomial whose zeroes are 1/5 and -4/7

Solution:

The given question can be solved as shown below.

The given roots α = 1/5 and β = -4/7

So the equation is of the form ( x - α )( x - β ) = 0

These terms in the equation should be multiplied to get the quadratic equation.

⇒ ( x - 1/5 )( x - ( -4/7) ) = 0

⇒ ( x - 1/5 )( x + 4/7 ) = 0

⇒ ( 5x - 1 )( 7x + 4 ) = 0

⇒ 35x² + 20x - 7x - 4 = 0

⇒ 35x² + 13x - 4 = 0

Therefore the required quadratic polynomial whose zeroes are 1/5 and -4/7 is '35x² + 13x - 4 = 0'.

#SPJ3