Question

Find quadratic polynomial whose zeroes are $3 - \sqrt{2 \: \: } and \: 3 + \sqrt{2}$ are​

Answer 1

Answer:

ax² + bx + c = p(x)

(3-√2) + (3+√2)= -b/a

9= -b/a

[ -(9)= b, a=1]

(3-√2)(3+√2)= c/a

9-2= 7/1

Therefore, p(x) = x² -9x + 7