Question

find quadratic polynomial whose zeros are 2 + under root 5 upon 2, 2 -under root 5 upon 2​

Answer 1

see

the question says to find quadratic polynomials whose zeros are 2+ under root 5 upon 2, 2-under root 5 upon 2 which i have not studied till now do i cant give the answer and sorry for this joke too....

Answer 2

zeroes are

$\alpha = \frac{2 + \sqrt{5} }{2} \: \: \: \: \: \: \: \: \: \: and \: \: \: \: \beta = \frac{2 - \sqrt{5} }{2} \\ \alpha + \beta = \frac{2 + \sqrt{5} + 2 - \sqrt{5} }{2} = 2 \\ \\ \alpha \beta = \frac{(2 + \sqrt{5})(2 - \sqrt{5}) }{4} = \frac{ {2}^{2} - { \sqrt{5} }^{2} }{4 } \\ \alpha \beta = \frac{ - 1}{4} \\ so \: equation \: is \: given \: by \\ {x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0 \\ {x}^{2} - 2x - \frac{1}{4} = 0 \\ 4 {x}^{2} - 8x - 1 = 0$
please mark it as brainliest