find quadratic polynomial whose zeros are 2and-6
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Answered by
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Answer:
Step-by-step explanation:
the formula of quadratic equation ia x2-(alpha+beta)+alpha*beta
alpha=2 beta=-6
so, the equation is
x2-(2+(-6))x+2*-6
x2-4x-12=0
the quadratic equation is x2-4x-12=0
proof:
x2+4x-12=0
by factorisation
x2-2x+6x-12=0
x commom
x(x-2)+6(x-2)=0
(x-2) is common
so,(x+2),(x-6) are the roots
X=2,-6
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