Question

find quadratic polynomial whose zeros are 3+√2 and 3-√2 .

Answer 1

let take a=3+√2
b=3-√2
sum of zeroes a+b=6
product of zeroes a×b=7
formula is x^2-x(a+b)+a×b
x^2-6x+7
this is the required polynomial

Answer 2

Heya!
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♦Quadratic Equation♦
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=> Given that ->


( 3 + √2 ) and ( 3 - √2 ) are the zeroes of the polynomial .


We have ,


=> Sum of Zeroes = 3 + √2 + 3 - √2


= > 6 ✔


=> Product of Zeroes = ( 3 + √2 ) ( 3 - √2 )

=> (3)² - (√2)²

=> 9 - 2 = 7 ✔



↪Using the Formula for p ( x ) = x² - sx + p { here s and p represent sum and product respectively }


=> P ( x ) = x² - 6x + 7



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