find quadratic polynomial whose zeros are 3 +√5and 3-√5
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✨ solution :
Let required polynomial be f(X)
then , x-(3+√5) and x-(3-√5) are factors of f(X) .
then ,
[x - (3 + √5)] [x - (3 - √5) is required polynomial
= [x - 3 - √5] [x - 3 + √5]
= x - 3x + √5x - 3x + 9 - 3 √5 - √5x +
3 √5 - 5
= x² - 6x + 4
or...
zeroes = 3+root5 and 3-root5
product of zeroes= (3+root5)(3-root5)
= 9-5
=4
sum of zeroes=3+root5 + 3-root5
=6
we know f(x) = k(x2^ - sum of zeroes (x) + product of zeroes
= k(x2^ -6x +4) is yr required answer ...
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