Question

find quadratic polynomials for given zeroes

underoot 2 and underoot -2​

Answer 1

Answer:

α = √2   β = -√2

k[ x² - (α+β) x + (αβ)]

k [x²-√2x +√2x - 2 ]

k [x² - 2]   (∵√2x and -√2x cancel each other out )

ANS =  k(x² - 2 )

Answer 2

Answer:

P(x) = x²- 2

Step-by-step explanation:

let x= under root 2

then p(underoot 2)=

${ \sqrt{2} }^{2} - 2 \\ = 2 - 2 \\ = 0$

so its clear that underoot 2 is zero of the p(x)

let x =underoot -2

then p(underoot -2)=

${ \sqrt{ - 2} }^{2} - 2 \\ = 2 - 2 \\ = 0$

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