Question

Find quadratic polynomil whose zeroes are -2 and 2

Answer 1

Answer: x^2 - 4

Step-by-step explanation:

Let a = -2 and B = 2

Therefore, p(x) = x^2 + (a+B)x + aB

= x^2 + [(-2) + 2]x + (-2)(2)

= x^2 + 0.x + (-4)

= x^2 -4