Question

find quadric polynomial eq if zeros of polynomial are 2,3​

Answer 1

Answer:

Step-by-step explanation:

two of its zeros are 2 and 3 $\alpha =2....\beta =3$

$x^{2} - (sum of numbers) x + product of numbers$

$x^{2} -(\alpha +\beta )x + \alpha \beta$

$x^{2} -(2+3)x + 2*3$

$x^{2} -5x + 6$