find quadric polynomial whose zeros are 5-3√2 and 5+3√2
Answers
Answered by
1
Answer:
x^2-10x+7
Step-by-step explanation:
If 5±3√2 are roots of polynomial then
x−(5+3√2) and x−(5−3√2) are factors of the polynomial
∴[x−(5+3√2)][x−(5−3√2)]
=x^2−x(5−3√2+5+3√2)+(5+3√2)(5−3√2)
=x^2−10x+(25−9(2))
=x^2−10x+7
Similar questions