Question

find Quantum no. value for 27th electron of element 34..​

Answer 1

Element 34 electronic configuration -

$[Ar]^{18}4s^{2}3d^{10}4p^{4}$

27th electron is in 3d-orbital.

Thus,

n = 3

l = 2

m = -2, -1, 0, 1, 2

s = +/- 1/2