find quardratic polynomial whose one of the zeros is _15 and sum ofzeros is 42
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Answered by
5
Heya !!!
Here is your answer.
Given :
Let a and b be two zeroes.
Sum of Zeroes, a + b = 42
One zero is -15 .
So, -15 + b = 42
b = 57
Now, product of zeroes = 57 × -15 = -855
Using
p(x) = kx² - ( sum of zeroes)x + (product of zeroes)
= x² - 42x + (-855)
= x² - 42x - 855
Hope It Helps
Here is your answer.
Given :
Let a and b be two zeroes.
Sum of Zeroes, a + b = 42
One zero is -15 .
So, -15 + b = 42
b = 57
Now, product of zeroes = 57 × -15 = -855
Using
p(x) = kx² - ( sum of zeroes)x + (product of zeroes)
= x² - 42x + (-855)
= x² - 42x - 855
Hope It Helps
RehanAhmadXLX:
Sorry. It happens when we are in a hurry
Answered by
4
Heya !!!
Let Alpha = -15
Sum of zeroes = 42
Alpha + Beta = 42
-15 + Beta = 42
Beta = 42+15
beta = 57
Product of zeroes = Alpha × beta = -15 × 57 = -855
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(42)X + (-855)
=> X²-42X - 855.
HOPE IT WILL HELP YOU....... :-)
Let Alpha = -15
Sum of zeroes = 42
Alpha + Beta = 42
-15 + Beta = 42
Beta = 42+15
beta = 57
Product of zeroes = Alpha × beta = -15 × 57 = -855
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(42)X + (-855)
=> X²-42X - 855.
HOPE IT WILL HELP YOU....... :-)
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