Find quardratic polynomial whose zeros are 5 and -3
Answers
Answered by
6
Step-by-step explanation:
given:-
zeros =5 , -3
sum of zeroes = -(cofficient of x/cofficient of x^2)
hence ,
5-3= -(cofficient of x/cofficient of x^2)
2=cofficient of x
1= cofficient of x^2
and also
product of zeroes = constant term /cofficient of x^2
5×3=constant term/cofficient of x^2
15=constant term
now we get ,
cofficient of x^2=1
cofficient of x=2
constant term=15
from all this we get the equation equals to ,
=> x^2+2x +15
hope it helps you
@Ar+nav
Similar questions