Find qudratic polynomial
of
(4,1/4)
(0,✓5)
Answers
Thnkx for asking question...
(1) (4,1/4)
Sum of zeroes =4
product of zeroes =1/4
Sum of zeroes are =-b/c
product of zeroes =a/c
Sum of zeroes =(-b/c)=-4/c
product of zeroes =a/c=1/4
It shows that
a=1
c=4
but
b=16 .....why ??
It is because Sum ofzeroes will be
-4/c =>>> c=4
-4*4/4
=> -16/4
hence b is 4
Otherwise if we fill like this ...i.e
-4/4=0 ....this is wrong ...
So we write it like 16/4=4 ...Ans .
Hope its help u
(0,✓5)
Sum of zeroes =(-b/c) = 0
product of zero = ✓5 = a/c
Both cases c =??
So it means c=1
Thus quadratic equation is in form
ax²+bx+c
✓5x²+0x+1 Ans ....
Hope its helps u
Answer:
quadratic equation with sum =4,product of roots =1/4
we know that quadratic equation x^2+(sum of roots)x+(product of roots)=0
x^2-4x+1/4=0
4x^2-16x+1=0
(0,√5)
sum of roots =0
product of roots=√5
y^2+(0)y+√5=0
y^2+√5=0
hope it helps
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