Question

find question 5 in the photograph pls fast.

Answer 1

AD / DB = AE /EC 

x /(x-2) = (x+2) / (x-1) 

Solving this , we get x = 4

Answer 2

HELLO DEAR,
$\frac{ad}{db} = \frac{ae}{ec} \\ = > \frac{x}{(x - 2)} = \frac{(x + 2)}{(x - 1)} \\ = > {x - x}^{2} = ( \: {x }^{2} - {x}^{2} ) \\ = > x = - {x}^{2} + {x}^{2} + {x }^{2} \\ = > then \: x = {x}^{2} \\ = > x = 1 \\ = > i \: hope \: its \: help \: you \: dear \: \\ thanks$