Question

Find quotient and remainder on dividing 6x²-5x+1 by 2x+1​

Answer 1

Answer:

Quotient = (3x-4)

Remainder = 5.

Answer 2

AnswEr:-

❀ Your Answers Are:-

• Quotient = 3x - 4.

• Remainder = 5.

ExplanaTion:-

Given:-

• Dividend = $\tt 6x^2-5x+1.$

• Divisor = 2x + 1.

And we have to divide Dividend by Divisor.

So By Long Division Method:-

$\hookrightarrow \boxed{\begin{array}\quad\begin{tabular}{m{3.5em}cccc}&& 3x& -4\\\cline{3-5}\multicolumn{2}{l}{2x + 1\big)}& \not{6x^2}& - 5x& + 1 \\&& \not{6x^2}&+3x&\\&&(-)&(-) &&\\ \cline{3-5}&&& \not{- 8x}& + 1\\&&& \not{ - 8x}&-4 \\ &&&(+)&(+)&\\ \cline{4-5}&&&& 5\\ \\\end{tabular}\end{array}}$