Find r'(t) and r''(t) for the given vector function f(t)= lnti+j, t>o
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Answer:
xample 2.4.1
Let
r(t)=ti^+etj^−3t2k^.
Find T(t) and T(0) .
Solution
We have
v(t)=r′(t)=i^+etj^−6tk^
and
||v(t)||=1+e2t+36t2−−−−−−−−−−−√.
To find the unit tangent vector, we just divide
T(t)=v(t)||V(T)||=i^+etj^−6tk^1+e2t+36t2−−−−−−−−−−−√.
To find T(0) plug in 0 to get
T(0)=i^+e0j^−6(0)k^1+e2(0)+36(0)2−−−−−−−−−−−−−−√=i^+j^2–√=12–√i^+12–√j^.
Step-by-step explanation:
tq
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