Find radius. No other
information given. All those
are squares
Answers
Given : A circle and three square inside of 6 , 12 & 18 sides
To find : Radius of circle
Solution:
Three squares : 6 * 6 , 12 * 12 & 18 * 18
as all these are squares
hence all horizontal lines are parallel to each other
We know that perpendicular bisector of chord passes through center of circle
=> Center will lie on perpendicular bisector of 6 & 18 length chord
& perpendicular bisector will be same line for both
Let say distance of center of circle from mid point of 6 length chord = x
then distance of center of circle from mid point of 18 length chord = 36 - x
Let Radius = R
=> R² = x² + 3² ( 6/2 = 3)
R² = (36 - x)² + 9² ( 18/2 = 9)
=> x² + 3² = (36 - x)² + 9²
=> x² + 9 = 36² + x² - 72x + 81
=> 72x = 36² + 72
=> x = 18 + 1
=> x = 19
R² = x² + 3²
=> R² = 19² + 3²
=> R² = 361 + 9
=> R² = 370
=> R = √370
=> R = 19.23
Radius of circle = √370 = 19.23
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