Math, asked by chintumisteu, 1 day ago

find ramaining portion ​
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Answered by MrFire07
3

⇒ Area of remaining portion

= Area of square

= Area of middle circle – Area of 4 quadrants

For square ABCD

Area of square = (side)²

‌‌‌‌‌ = (4)²

‌‌‌‌‌ = 4 × 4

‌‌‌‌‌ = 16

For middle circle

Diameter = 2 cm

Hence, radius = r =  \frac{Diameter}{2} =  \frac{2}{2} = 1 cm

Area of middle circle = πr²

‌‌‌‌‌ ‌‌‌‌‌ ‌‌‌‌‌ =  \frac{22}{7} × 1 × 1

For quadrant

radius = r = 1 cm

Area of 1 quadrant =  \frac{1}{4} of (area of circle)

‌‌‌‌‌ ‌‌‌‌‌ ‌‌‌‌‌ =  \frac{1}{4} × πr²

‌‌‌‌‌ ‌‌‌‌‌ ‌‌‌‌‌ =  \frac{1}{4} ×  \frac{22}{7} × 1²

‌‌‌‌‌ ‌‌‌‌‌ ‌‌‌‌‌ =  \frac{22}{8} × πr²

For middle circle

Diameter = 2 cm

Hence, radius = r =  \frac{Diameter}{2} =  \frac{2}{2} = 1 cm

Area of middle circle = πr²

‌‌‌‌‌ ‌‌‌‌‌ ‌‌‌‌‌ =  \frac{22}{7} × 1 × 1

For quadrant

radius = r = 1 cm

Area of 1 quadrant =  \frac{1}{4} of (area of circle)

‌‌‌‌‌ ‌‌‌‌‌ ‌‌‌‌‌ =  \frac{1}{4} × πr²

‌‌‌‌‌ ‌‌‌‌‌ ‌‌‌‌‌ =  \frac{1}{4} ×  \frac{22}{7} × 1²

‌‌‌‌‌ ‌‌‌‌‌ ‌‌‌‌‌ =  \frac{22}{28}

‌‌‌‌‌ ‌‌‌‌‌ ‌‌‌‌‌ =  \frac{68}{7} cm²

Hence, area of remaining portion =  \frac{68}{7} cm²

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