Question

find range of 1/cos(sin^-1(sinx+cosx))
​

Answer 1

Step-by-step explanation:

range of sin

−1

xϵ[−

2

π

,

2

π

]

range of cos

−1

xϵ[0,π]

∴f(x)=sin

−1

x−cos

−1

x=sin

−1

x+cos

−1

x−2cos

−1

x

=

2

π

−2cos

−1

x[∵sin

−1

x+cos

−1

x=

2

π

]identity

range of f(x)ϵ[

2

π

−2(π),

2

π

−2(0)]

∴f(x)ϵ[−

2

3π

,

2

π

] please follow me