Question

find range of e^2x+1/e^2x-1​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

f(x) = [(e2x – 1)/(e2x + 1)] ∴ f'(x) = [{[(e2x + 1) (e2x) – (e2x – 1)(e2x)]2}/{(e2x + 1)2}] = [{[e2x + e2x – e4x + e2x] × 2}/{(1 + e2x)2}] = [{4e2x}/{(1 + e2x)2}] f'(x) = [{4e2x}/{(1 + e2x)2}] > 0  ⇒ f(x) is increasing function

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